Eigenvalues and eigenvectors of the second derivative
Encyclopedia
Explicit formulas for eigenvalues and eigenvectors of the second derivative
Second derivative
In calculus, the second derivative of a function ƒ is the derivative of the derivative of ƒ. Roughly speaking, the second derivative measures how the rate of change of a quantity is itself changing; for example, the second derivative of the position of a vehicle with respect to time is...

with different boundary conditions are provided both for the continuous and discrete cases. In the discrete case, the standard central difference approximation of the second derivative is used on a uniform grid.

These formulas are used to derive the expressions for eigenfunctions of Laplacian in case of separation of variables
Separation of variables
In mathematics, separation of variables is any of several methods for solving ordinary and partial differential equations, in which algebra allows one to rewrite an equation so that each of two variables occurs on a different side of the equation....

, as well as to find eigenvalues and eigenvectors of multidimensional discrete Laplacian
Discrete Laplace operator
In mathematics, the discrete Laplace operator is an analog of the continuous Laplace operator, defined so that it has meaning on a graph or a discrete grid...

 on a regular grid
Regular grid
A regular grid is a tessellation of n-dimensional Euclidean space by congruent parallelotopes . Grids of this type appear on graph paper and may be used in finite element analysis as well as finite volume methods and finite difference methods...

, which is presented as a Kronecker sum of discrete Laplacians
Kronecker sum of discrete Laplacians
In mathematics, the Kronecker sum of discrete Laplacians, named after Leopold Kronecker, is a discrete version of the separation of variables for the continuous Laplacian in a rectangular cuboid domain.-General form of the Kronecker sum of discrete Laplacians:...

 in one-dimension.

The continuous case

The index j represents the jth eigenvalue or eigenvector and runs from 1 to . Assuming the equation is defined on the domain , the following are the eigenvalues and normalized eigenvectors. The eigenvalues are ordered in descending order.

Pure Dirichlet boundary conditions



Pure Neumann boundary conditions



Periodic boundary conditions



(Note that eigenvalues are repeated except for 0 eigenvalue.)

Mixed Dirichlet-Neumann boundary conditions



Mixed Neumann-Dirichlet boundary conditions



The discrete case

Notation: The index j represents the jth eigenvalue or eigenvector. The index i represents the ith component of an eigenvector. Both i and j go from 1 to n, where the matrix is size n x n. Eigenvectors are normalized. The eigenvalues are ordered in descending order.

Pure Dirichlet boundary conditions



Pure Neumann boundary conditions



Periodic boundary conditions



(Note that eigenvalues are repeated except for 0 and the largest one if n is even.)

Mixed Dirichlet-Neumann boundary conditions



Mixed Neumann-Dirichlet boundary conditions



Dirichlet case

In the 1D discrete case with Dirichlet boundary conditions, we are solving


Rearranging terms, we get


Now let . Also, assuming , we can scale eigenvectors by any nonzero scalar, so scale so that .

Then we find the recurrence




Considering as an indeterminate,

where is the kth Chebyshev polynomial
Chebyshev polynomials
In mathematics the Chebyshev polynomials, named after Pafnuty Chebyshev, are a sequence of orthogonal polynomials which are related to de Moivre's formula and which can be defined recursively. One usually distinguishes between Chebyshev polynomials of the first kind which are denoted Tn and...

 of the 2nd kind.

Since , we get that
.

It is clear that the eigenvalues of our problem will be the zeros of the nth Chebyshev polynomial of the second kind, with the relation .

These zeros are well known and are:


Plugging these into the formula for ,


And using a trig formula to simplify, we find

Neumann case

In the Neumann case, we are solving


In the standard discretization, we introduce and and define


The boundary conditions are then equivalent to

If we make a change of variables,

we can derive the following:

with being the boundary conditions.

This is precisely the Dirichlet formula with interior grid points and grid spacing . Similar to what we saw in the above, assuming , we get


This gives us eigenvalues and there are . If we drop the assumption that , we find there is also a solution with and this corresponds to eigenvalue .

Relabeling the indices in the formula above and combining with the zero eigenvalue, we obtain,

Dirichlet-Neumann Case

For the Dirichlet-Neumann case, we are solving
,

where

We need to introduce auxiliary variables

Consider the recurrence
.

Also, we know and assuming , we can scale so that

We can also write

Taking the correct combination of these three equations, we can obtain


And thus our new recurrence will solve our eigenvalue problem when


Solving for we get


Our new recurrence gives


where again is the kth Chebyshev polynomial
Chebyshev polynomials
In mathematics the Chebyshev polynomials, named after Pafnuty Chebyshev, are a sequence of orthogonal polynomials which are related to de Moivre's formula and which can be defined recursively. One usually distinguishes between Chebyshev polynomials of the first kind which are denoted Tn and...

 of the 2nd kind.

And combining with our Neumann boundary condition, we have


A well-known formula relates the Chebyshev polynomials
Chebyshev polynomials
In mathematics the Chebyshev polynomials, named after Pafnuty Chebyshev, are a sequence of orthogonal polynomials which are related to de Moivre's formula and which can be defined recursively. One usually distinguishes between Chebyshev polynomials of the first kind which are denoted Tn and...

of the first kind, , to those of the second kind by


Thus our eigenvalues solve


The zeros of this polynomial are also known to be


And thus


Note that there are 2n + 1 of these values, but only the first n + 1 are unique. The (n + 1)th value gives us the zero vector as an eigenvector with eigenvalue 0, which is trivial. This can be seen by returning to the original recurrence. So we consider only the first n of these values to be the n eigenvalues of the Dirichlet - Neumann problem.
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